# ds1000 / 149

- taskset: [ds1000](https://harnessreport.com/tasks/ds1000.md)
- difficulty: 
- category: 
- language: 
- runnable from the site: no
- agent timeout: 1800s

## Results by harness

_none yet_

## Instruction

```
# 149: DS-1000 Task

## Prompt
Problem:
Example
import pandas as pd
import numpy as np
d = {'l':  ['left', 'right', 'left', 'right', 'left', 'right'],
     'r': ['right', 'left', 'right', 'left', 'right', 'left'],
     'v': [-1, 1, -1, 1, -1, np.nan]}
df = pd.DataFrame(d)


Problem
When a grouped dataframe contains a value of np.NaN I want the grouped sum to be NaN as is given by the skipna=False flag for pd.Series.sum and also pd.DataFrame.sum however, this
In [235]: df.v.sum(skipna=False)
Out[235]: nan


However, this behavior is not reflected in the pandas.DataFrame.groupby object
In [237]: df.groupby('r')['v'].sum()['right']
Out[237]: 2.0


and cannot be forced by applying the np.sum method directly
In [238]: df.groupby('r')['v'].apply(np.sum)['right']
Out[238]: 2.0


desired:
r
left     NaN
right   -3.0
Name: v, dtype: float64


A:
<code>
import pandas as pd
import numpy as np


d = {'l':  ['left', 'right', 'left', 'right', 'left', 'right'],
     'r': ['right', 'left', 'right', 'left', 'right', 'left'],
     'v': [-1, 1, -1, 1, -1, np.nan]}
df = pd.DataFrame(d)
</code>
result = ... # put solution in this variable
BEGIN SOLUTION
<code>

## What to do
- Edit `solution/solution.py` so the code passes the DS-1000 tests.
- Do not access the internet or install new packages; required libraries are preinstalled in the Docker image.
- Run tests locally via `bash tests/test.sh`.

## Notes
- Keep the variable names/signatures implied by the prompt/code_context.
- The evaluator uses the original DS-1000 `code_context` (`test_execution` / `test_string`).
```
---
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